How to print perfect squares between 1 to 100 in C++

Program to check perfect squares between 1 to 100

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#include<iostream>

#include<conio.h>

using namespace std;

int perfect_square(int number);

int main()

{

       int number = 0, perfect_sq = 0;

       cout << "\n\n\t\t __ Program to print Perfect Square betwenen 1 to 100 __";

       cout << "\n\n\n  Perfect Squares  -  ";

       for(number = 1; ; number++)

       {

              perfect_sq = perfect_square(number);

              if (perfect_sq <= 100)

              {

                     cout << perfect_sq << " , ";

              }

              else

              {

                     break;

              }

       }

       cout << "\b\b  ";

       getch();

       return 0;

}

int perfect_square(int number)

{

       return number * number;

}

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A number is said to be a perfect square is it is the square of any other number. For Example – 0, 1, 4, 9, 16, 25 etc. or in other words it can be said that if the square of a number is a whole number then it’s a perfect square.