How to print the perfect numbers between 1 to 100 in C++

Program to print perfect numbers between 1 to 100

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#include<iostream>

#include<conio.h>

using namespace std;

int main()

{

       int number = 1, counter = 0, sum = 0;

       cout << "\n\n\t  Program to print perfect numbers between 1 to 100\n\n";

       cout << "\n\n\t  Perfect Numbers - ";

       for(number = 1 ; number <= 100; number++)

       {

              sum = 0;

              for(counter = 1; counter < number; counter++)

              {

                     if ((number % counter) == 0)

                     {

                           sum = sum + counter;

                     }

              }

              if (sum == number)

              {

                     cout  << number << " , ";

              }

       }

       cout << "\b\b" << " " ;

       getch();

       return 0;

}

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An integer is said to be a perfect number if the sum of the its factor including 1 (but not the number itself) is equal to its number. For Example - 6 is a perfect number, because 6 = 1 + 2 + 3.