How to find the sum of digits of a 5 digit number using recursion in C++

Calculate the sum of the digits of a 5 digit number using recursion

---

#include<iostream>

#include<conio.h>

using namespace std;

int check_five(int number);

int add(int number);

int main()

{

       int number = 0, sum = 0, remainder = 0, temp = 0, check = 0;

       while(check != 1)

       {

              system("cls");

              cout << "\n    __ Program to calculate the sum of the digits of 5 digit number ___";

      

              cout << "\n\n\n  Enter the Number - ";

              cin >> number;

              check = check_five(number);

              if (check == 0)

              {

                     //__ Error Message____

                     cout << "\n\n\t\t____ 5 digit number is required ____";

                     cout << "\n\n\n  Press Enter to Continue....";

                     while(getch() != 13)

                     {

                     }

              }

       }

             

       sum = add(number);

       cout << "\n\n  The sum of the digits of number " << number << " is " << sum;

       getch();

       return 0;

}

int check_five(int number)

{

       int remainder = 0, counter = 0;

       while(number != 0)

       {

              remainder = number % 10;

              number = number / 10;

              counter++;

       }

       if (counter == 5)   

             

       /*___ Change 5 to make this program for any digit number, but do check the value of integer

       before doing that */

       {

              return 1;

       }

       else

       {

              return 0;

       }

}

int add(int number)

{

       if(number == 0)

       {

              return 0;

       }

       else

       {

              return (number % 10) + add(number/10);

       }

}