How to check whether a number is an armstrong number or not in C++

Program to check a number for being Armstrong number

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#include<iostream>

#include<conio.h>         

using namespace std;

int main()

{

  int number = 0, temp_number = 0, remainder = 0, number_cube = 0;          

  cout << "\n\n     ______ Program to check a number for being Armstrong ______";

       cout << "\n\n\n  Enter the Number  ->  ";

       cin >> number;

      

       number_cube = 0;

       temp_number = number;

      

       while(temp_number != 0)

       {

              remainder = temp_number % 10;

             

              temp_number = temp_number / 10;

             

              number_cube = number_cube + remainder * remainder * remainder;      

       }

       cout << "\n\n\t\t";

       if (number_cube == number)       

       {

              cout << number << " is an Armstrong number";

       }

       else

       {

              cout << number << " is not an Armstrong number";

       }

      

       getch();

       return 0;                        

}

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A number is an Armstrong number if the sum of the cube of its digits is equal to the original number.